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12012121330230 = 2357241405149199
BaseRepresentation
bin1010111011001100101000…
…1110011001001000110110
31120112100101101111110221010
42232303022032121020312
53033301311030031410
641314143052133050
72346563364430500
oct256631216311066
946470341443833
1012012121330230
11391134837669a
121420043167186
13691979a25938
142d7565780d70
1515c6e215ac20
hexaecca399236

12012121330230 has 192 divisors, whose sum is σ = 34363008691200. Its totient is φ = 2677945536000.

The previous prime is 12012121330219. The next prime is 12012121330283. The reversal of 12012121330230 is 3203312121021.

12012121330230 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a junction number, because it is equal to n+sod(n) for n = 12012121330197 and 12012121330206.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 244129171 + ... + 244178369.

It is an arithmetic number, because the mean of its divisors is an integer number (178974003600).

Almost surely, 212012121330230 is an apocalyptic number.

12012121330230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 12012121330230, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17181504345600).

12012121330230 is an abundant number, since it is smaller than the sum of its proper divisors (22350887360970).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12012121330230 is a wasteful number, since it uses less digits than its factorization.

12012121330230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53315 (or 53308 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 12012121330230 its reverse (3203312121021), we get a palindrome (15215433451251).

The spelling of 12012121330230 in words is "twelve trillion, twelve billion, one hundred twenty-one million, three hundred thirty thousand, two hundred thirty".