Search a number
-
+
12012132200303 = 83144724484341
BaseRepresentation
bin1010111011001100101011…
…0111110110111101101111
31120112100102010221201212102
42232303022313312331233
53033301321320402203
641314144121125315
72346563556012614
oct256631267667557
946470363851772
1012012132200303
113911353520524
12142004692983b
1369197c060531
142d7566db050b
1515c6e30a6888
hexaeccadf6f6f

12012132200303 has 4 divisors (see below), whose sum is σ = 12156856684728. Its totient is φ = 11867407715880.

The previous prime is 12012132200293. The next prime is 12012132200309. The reversal of 12012132200303 is 30300223121021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12012132200303 - 240 = 10912620572527 is a prime.

It is a super-2 number, since 2×120121322003032 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012132200309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72362242088 + ... + 72362242253.

It is an arithmetic number, because the mean of its divisors is an integer number (3039214171182).

Almost surely, 212012132200303 is an apocalyptic number.

12012132200303 is a deficient number, since it is larger than the sum of its proper divisors (144724484425).

12012132200303 is an equidigital number, since it uses as much as digits as its factorization.

12012132200303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144724484424.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 12012132200303 its reverse (30300223121021), we get a palindrome (42312355321324).

The spelling of 12012132200303 in words is "twelve trillion, twelve billion, one hundred thirty-two million, two hundred thousand, three hundred three".

Divisors: 1 83 144724484341 12012132200303