Base | Representation |
---|---|
bin | 10110010111111101… |
… | …11001111111111101 |
3 | 1011000011001222111211 |
4 | 23023332321333331 |
5 | 144100110344213 |
6 | 5303543044421 |
7 | 603450005026 |
oct | 131376717775 |
9 | 34004058454 |
10 | 12012199933 |
11 | 5104634668 |
12 | 23b2a40711 |
13 | 1195846816 |
14 | 81d4b5c4d |
15 | 4a488053d |
hex | 2cbfb9ffd |
12012199933 has 2 divisors, whose sum is σ = 12012199934. Its totient is φ = 12012199932.
The previous prime is 12012199861. The next prime is 12012200029. The reversal of 12012199933 is 33999121021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9697916484 + 2314283449 = 98478^2 + 48107^2 .
It is an emirp because it is prime and its reverse (33999121021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12012199933 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12012199333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006099966 + 6006099967.
It is an arithmetic number, because the mean of its divisors is an integer number (6006099967).
Almost surely, 212012199933 is an apocalyptic number.
It is an amenable number.
12012199933 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012199933 is an equidigital number, since it uses as much as digits as its factorization.
12012199933 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 40.
The spelling of 12012199933 in words is "twelve billion, twelve million, one hundred ninety-nine thousand, nine hundred thirty-three".
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