1201220011211 has 4 divisors (see below), whose sum is σ = 1310421830424. Its totient is φ = 1092018192000.

The previous prime is 1201220011183. The next prime is 1201220011219. The reversal of 1201220011211 is 1121100221021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201220011211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1201220011219) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54600909590 + ... + 54600909611.

It is an arithmetic number, because the mean of its divisors is an integer number (327605457606).

Almost surely, 2^{1201220011211} is an apocalyptic number.

1201220011211 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1201220011211 is a deficient number, since it is larger than the sum of its proper divisors (109201819213).

1201220011211 is a wasteful number, since it uses less digits than its factorization.

1201220011211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 109201819212.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 1201220011211 its reverse (1121100221021), we get a palindrome (2322320232232).

The spelling of 1201220011211 in words is "one trillion, two hundred one billion, two hundred twenty million, eleven thousand, two hundred eleven".