Base | Representation |
---|---|
bin | 1010111011001100111011… |
… | …1111010101111101010001 |
3 | 1120112100120221220220012212 |
4 | 2232303032333111331101 |
5 | 3033301442011133441 |
6 | 41314155025401505 |
7 | 2346565355056352 |
oct | 256631677257521 |
9 | 46470527826185 |
10 | 12012201271121 |
11 | 3911389507447 |
12 | 1420065a99295 |
13 | 69199046513c |
14 | 2d757222dd29 |
15 | 15c6e919beeb |
hex | aeccefd5f51 |
12012201271121 has 2 divisors, whose sum is σ = 12012201271122. Its totient is φ = 12012201271120.
The previous prime is 12012201271117. The next prime is 12012201271129. The reversal of 12012201271121 is 12117210221021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11584663140625 + 427538130496 = 3403625^2 + 653864^2 .
It is an emirp because it is prime and its reverse (12117210221021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12012201271121 - 22 = 12012201271117 is a prime.
It is not a weakly prime, because it can be changed into another prime (12012201271129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006100635560 + 6006100635561.
It is an arithmetic number, because the mean of its divisors is an integer number (6006100635561).
Almost surely, 212012201271121 is an apocalyptic number.
It is an amenable number.
12012201271121 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012201271121 is an equidigital number, since it uses as much as digits as its factorization.
12012201271121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 12012201271121 its reverse (12117210221021), we get a palindrome (24129411492142).
The spelling of 12012201271121 in words is "twelve trillion, twelve billion, two hundred one million, two hundred seventy-one thousand, one hundred twenty-one".
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