120122110000993 has 2 divisors, whose sum is σ = 120122110000994. Its totient is φ = 120122110000992.

The previous prime is 120122110000957. The next prime is 120122110001039. The reversal of 120122110000993 is 399000011221021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 89336390914849 + 30785719086144 = 9451793^2 + 5548488^2 .

It is a cyclic number.

It is not a de Polignac number, because 120122110000993 - 2²¹ = 120122107903841 is a prime.

It is a super-2 number, since 2×120122110000993² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120122110004993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60061055000496 + 60061055000497.

It is an arithmetic number, because the mean of its divisors is an integer number (60061055000497).

Almost surely, 2^{120122110000993} is an apocalyptic number.

It is an amenable number.

120122110000993 is a deficient number, since it is larger than the sum of its proper divisors (1).

120122110000993 is an equidigital number, since it uses as much as digits as its factorization.

120122110000993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 31.

The spelling of 120122110000993 in words is "one hundred twenty trillion, one hundred twenty-two billion, one hundred ten million, nine hundred ninety-three", and thus it is an aban number.