Base | Representation |
---|---|
bin | 10001011110101110010… |
… | …111001110110100111010 |
3 | 11020211120011121120002220 |
4 | 101132232113032310322 |
5 | 124140100111414320 |
6 | 2315500003104510 |
7 | 152533244512302 |
oct | 21365627166472 |
9 | 4224504546086 |
10 | 1201221201210 |
11 | 423487063698 |
12 | 17497a672136 |
13 | 893755c3284 |
14 | 421d47b6602 |
15 | 213a7012e40 |
hex | 117ae5ced3a |
1201221201210 has 32 divisors (see below), whose sum is σ = 2889778730112. Its totient is φ = 319564781760.
The previous prime is 1201221201161. The next prime is 1201221201247. The reversal of 1201221201210 is 121021221021.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 1201221201210.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 47541654 + ... + 47566913.
It is an arithmetic number, because the mean of its divisors is an integer number (90305585316).
Almost surely, 21201221201210 is an apocalyptic number.
1201221201210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1201221201210 is an abundant number, since it is smaller than the sum of its proper divisors (1688557528902).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201221201210 is a wasteful number, since it uses less digits than its factorization.
1201221201210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95108998.
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 1201221201210 its reverse (121021221021), we get a palindrome (1322242422231).
The spelling of 1201221201210 in words is "one trillion, two hundred one billion, two hundred twenty-one million, two hundred one thousand, two hundred ten".
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