Base | Representation |
---|---|
bin | 1010111011001101000000… |
… | …1011000111001000011111 |
3 | 1120112100122100022000001201 |
4 | 2232303100023013020133 |
5 | 3033302012102231333 |
6 | 41314201015220331 |
7 | 2346566015642614 |
oct | 256632013071037 |
9 | 46470570260051 |
10 | 12012221133343 |
11 | 3911399743202 |
12 | 14200706776a7 |
13 | 6919945ca932 |
14 | 2d7574b2050b |
15 | 15c6eacc217d |
hex | aecd02c721f |
12012221133343 has 2 divisors, whose sum is σ = 12012221133344. Its totient is φ = 12012221133342.
The previous prime is 12012221133323. The next prime is 12012221133379. The reversal of 12012221133343 is 34333112221021.
12012221133343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12012221133343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12012221133323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006110566671 + 6006110566672.
It is an arithmetic number, because the mean of its divisors is an integer number (6006110566672).
Almost surely, 212012221133343 is an apocalyptic number.
12012221133343 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012221133343 is an equidigital number, since it uses as much as digits as its factorization.
12012221133343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 12012221133343 its reverse (34333112221021), we get a palindrome (46345333354364).
The spelling of 12012221133343 in words is "twelve trillion, twelve billion, two hundred twenty-one million, one hundred thirty-three thousand, three hundred forty-three".
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