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120122219489 is a prime number
BaseRepresentation
bin110111111011111010…
…1111001101111100001
3102111001112011000010012
41233313311321233201
53432002242010424
6131103340014305
711451512006306
oct1576765715741
9374045130105
10120122219489
1146a41952468
121b344831395
13b43460a5ac
145b5767d0ad
1531d0a98b0e
hex1bf7d79be1

120122219489 has 2 divisors, whose sum is σ = 120122219490. Its totient is φ = 120122219488.

The previous prime is 120122219479. The next prime is 120122219491. The reversal of 120122219489 is 984912221021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114097355089 + 6024864400 = 337783^2 + 77620^2 .

It is a cyclic number.

It is not a de Polignac number, because 120122219489 - 28 = 120122219233 is a prime.

It is a super-2 number, since 2×1201222194892 (a number of 23 digits) contains 22 as substring.

Together with 120122219491, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (120122219429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60061109744 + 60061109745.

It is an arithmetic number, because the mean of its divisors is an integer number (60061109745).

Almost surely, 2120122219489 is an apocalyptic number.

It is an amenable number.

120122219489 is a deficient number, since it is larger than the sum of its proper divisors (1).

120122219489 is an equidigital number, since it uses as much as digits as its factorization.

120122219489 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 41.

The spelling of 120122219489 in words is "one hundred twenty billion, one hundred twenty-two million, two hundred nineteen thousand, four hundred eighty-nine".