Search a number
-
+
1201232330131 is a prime number
BaseRepresentation
bin10001011110101111000…
…001101011110110010011
311020211120221112222010011
4101132233001223312103
5124140110434031011
62315501041415351
7152533441223161
oct21365701536623
94224527488104
101201232330131
11423492374a49
1217498233a557
13893779bb932
14421d6072231
15213a7eb0621
hex117af06bd93

1201232330131 has 2 divisors, whose sum is σ = 1201232330132. Its totient is φ = 1201232330130.

The previous prime is 1201232330119. The next prime is 1201232330167. The reversal of 1201232330131 is 1310332321021.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1201232330131 is a prime.

It is a super-2 number, since 2×12012323301312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1201232330171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600616165065 + 600616165066.

It is an arithmetic number, because the mean of its divisors is an integer number (600616165066).

Almost surely, 21201232330131 is an apocalyptic number.

1201232330131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201232330131 is an equidigital number, since it uses as much as digits as its factorization.

1201232330131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1201232330131 its reverse (1310332321021), we get a palindrome (2511564651152).

The spelling of 1201232330131 in words is "one trillion, two hundred one billion, two hundred thirty-two million, three hundred thirty thousand, one hundred thirty-one".