Search a number
-
+
12012540376547 is a prime number
BaseRepresentation
bin1010111011001110001100…
…1100111011010111100011
31120112101110121000020102002
42232303203030323113203
53033303140314022142
641314252421514215
72346606643320044
oct256634314732743
946471417006362
1012012540376547
113911542970367
12142013b57296b
13691a157a5539
142d75a52a28cb
1515c718d32a32
hexaece333b5e3

12012540376547 has 2 divisors, whose sum is σ = 12012540376548. Its totient is φ = 12012540376546.

The previous prime is 12012540376481. The next prime is 12012540376549. The reversal of 12012540376547 is 74567304521021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12012540376547 - 224 = 12012523599331 is a prime.

It is a super-2 number, since 2×120125403765472 (a number of 27 digits) contains 22 as substring.

Together with 12012540376549, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12012540376549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006270188273 + 6006270188274.

It is an arithmetic number, because the mean of its divisors is an integer number (6006270188274).

Almost surely, 212012540376547 is an apocalyptic number.

12012540376547 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012540376547 is an equidigital number, since it uses as much as digits as its factorization.

12012540376547 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1411200, while the sum is 47.

Adding to 12012540376547 its reverse (74567304521021), we get a palindrome (86579844897568).

The spelling of 12012540376547 in words is "twelve trillion, twelve billion, five hundred forty million, three hundred seventy-six thousand, five hundred forty-seven".