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120129983 is a prime number
BaseRepresentation
bin1110010100100…
…00100110111111
322101001020100122
413022100212333
5221223124413
615530445155
72656042121
oct712204677
9271036318
10120129983
11618a0486
12342937bb
131bb7113c
1411d51211
15a82e108
hex72909bf

120129983 has 2 divisors, whose sum is σ = 120129984. Its totient is φ = 120129982.

The previous prime is 120129953. The next prime is 120130001. The reversal of 120129983 is 389921021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120129983 - 210 = 120128959 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120129953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60064991 + 60064992.

It is an arithmetic number, because the mean of its divisors is an integer number (60064992).

Almost surely, 2120129983 is an apocalyptic number.

120129983 is a deficient number, since it is larger than the sum of its proper divisors (1).

120129983 is an equidigital number, since it uses as much as digits as its factorization.

120129983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 35.

The square root of 120129983 is about 10960.3824294593. The cubic root of 120129983 is about 493.4204426266.

The spelling of 120129983 in words is "one hundred twenty million, one hundred twenty-nine thousand, nine hundred eighty-three".