120130001113 has 8 divisors (see below), whose sum is σ = 121592717568. Its totient is φ = 118667650704.

The previous prime is 120130001081. The next prime is 120130001153. The reversal of 120130001113 is 311100031021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 120130001113 - 2⁵ = 120130001081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120130001093 and 120130001102.

It is not an unprimeable number, because it can be changed into a prime (120130001153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 600495 + ... + 775147.

It is an arithmetic number, because the mean of its divisors is an integer number (15199089696).

Almost surely, 2^120130001113 is an apocalyptic number.

It is an amenable number.

120130001113 is a deficient number, since it is larger than the sum of its proper divisors (1462716455).

120130001113 is an equidigital number, since it uses as much as digits as its factorization.

120130001113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 183023.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 120130001113 its reverse (311100031021), we get a palindrome (431230032134).

The spelling of 120130001113 in words is "one hundred twenty billion, one hundred thirty million, one thousand, one hundred thirteen".