Base | Representation |
---|---|
bin | 11011010100000111111001… |
… | …110010010111110001110101 |
3 | 120202100022212101021110022221 |
4 | 123110013321302113301311 |
5 | 111221203002021030310 |
6 | 1103255004220322341 |
7 | 34206054430544416 |
oct | 3324077162276165 |
9 | 522308771243287 |
10 | 120130131033205 |
11 | 353059a2200547 |
12 | 115820359a33b1 |
13 | 52052b84bc337 |
14 | 2194487ac780d |
15 | dd4cd8c4dada |
hex | 6d41f9c97c75 |
120130131033205 has 16 divisors (see below), whose sum is σ = 144305213875200. Its totient is φ = 96004748518272.
The previous prime is 120130131033197. The next prime is 120130131033221. The reversal of 120130131033205 is 502330131031021.
It is a cyclic number.
It is not a de Polignac number, because 120130131033205 - 23 = 120130131033197 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 120130131033205.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 64577212 + ... + 66411418.
It is an arithmetic number, because the mean of its divisors is an integer number (9019075867200).
Almost surely, 2120130131033205 is an apocalyptic number.
It is an amenable number.
120130131033205 is a deficient number, since it is larger than the sum of its proper divisors (24175082841995).
120130131033205 is a wasteful number, since it uses less digits than its factorization.
120130131033205 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1847748.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 120130131033205 its reverse (502330131031021), we get a palindrome (622460262064226).
The spelling of 120130131033205 in words is "one hundred twenty trillion, one hundred thirty billion, one hundred thirty-one million, thirty-three thousand, two hundred five".
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