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12013022201321 is a prime number
BaseRepresentation
bin1010111011001111111111…
…1010111100010111101001
31120112102201011122110202002
42232303333322330113221
53033310132140420241
641314412313020345
72346624613625021
oct256637772742751
946472634573662
1012013022201321
11391176a943459
1214202549b46b5
13691a9156595b
142d760d286a81
1515c7462aa89b
hexaecffebc5e9

12013022201321 has 2 divisors, whose sum is σ = 12013022201322. Its totient is φ = 12013022201320.

The previous prime is 12013022201291. The next prime is 12013022201333. The reversal of 12013022201321 is 12310222031021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11448173755225 + 564848446096 = 3383515^2 + 751564^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013022201321 - 210 = 12013022200297 is a prime.

It is a super-3 number, since 3×120130222013213 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12013022201293 and 12013022201302.

It is not a weakly prime, because it can be changed into another prime (12013022206321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006511100660 + 6006511100661.

It is an arithmetic number, because the mean of its divisors is an integer number (6006511100661).

Almost surely, 212013022201321 is an apocalyptic number.

It is an amenable number.

12013022201321 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013022201321 is an equidigital number, since it uses as much as digits as its factorization.

12013022201321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 12013022201321 its reverse (12310222031021), we get a palindrome (24323244232342).

The spelling of 12013022201321 in words is "twelve trillion, thirteen billion, twenty-two million, two hundred one thousand, three hundred twenty-one".