Base | Representation |
---|---|
bin | 10110011000000100… |
… | …00100111100011101 |
3 | 1011000012122012210101 |
4 | 23030002010330131 |
5 | 144100313444242 |
6 | 5304012541101 |
7 | 603460036366 |
oct | 131402047435 |
9 | 34005565711 |
10 | 12013031197 |
11 | 5105052162 |
12 | 23b3181791 |
13 | 1195a77cab |
14 | 81d650b6d |
15 | 4a49969b7 |
hex | 2cc084f1d |
12013031197 has 2 divisors, whose sum is σ = 12013031198. Its totient is φ = 12013031196.
The previous prime is 12013031179. The next prime is 12013031207. The reversal of 12013031197 is 79113031021.
Together with previous prime (12013031179) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8913436921 + 3099594276 = 94411^2 + 55674^2 .
It is an emirp because it is prime and its reverse (79113031021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12013031197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12013032197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006515598 + 6006515599.
It is an arithmetic number, because the mean of its divisors is an integer number (6006515599).
Almost surely, 212013031197 is an apocalyptic number.
It is an amenable number.
12013031197 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013031197 is an equidigital number, since it uses as much as digits as its factorization.
12013031197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134, while the sum is 28.
The spelling of 12013031197 in words is "twelve billion, thirteen million, thirty-one thousand, one hundred ninety-seven".
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