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120130331197 is a prime number
BaseRepresentation
bin110111111100001010…
…0110110001000111101
3102111002002102010021211
41233320110312020331
53432011331044242
6131104225524421
711451640652512
oct1577024661075
9374062363254
10120130331197
1146a46492958
121b3474a3711
13b4361ba816
145b58791309
1531d164c317
hex1bf853623d

120130331197 has 2 divisors, whose sum is σ = 120130331198. Its totient is φ = 120130331196.

The previous prime is 120130331179. The next prime is 120130331213. The reversal of 120130331197 is 791133031021.

Together with previous prime (120130331179) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105918353401 + 14211977796 = 325451^2 + 119214^2 .

It is an emirp because it is prime and its reverse (791133031021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120130331197 - 215 = 120130298429 is a prime.

It is a super-2 number, since 2×1201303311972 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120130331107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065165598 + 60065165599.

It is an arithmetic number, because the mean of its divisors is an integer number (60065165599).

Almost surely, 2120130331197 is an apocalyptic number.

It is an amenable number.

120130331197 is a deficient number, since it is larger than the sum of its proper divisors (1).

120130331197 is an equidigital number, since it uses as much as digits as its factorization.

120130331197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3402, while the sum is 31.

The spelling of 120130331197 in words is "one hundred twenty billion, one hundred thirty million, three hundred thirty-one thousand, one hundred ninety-seven".