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120130711175 = 524805228447
BaseRepresentation
bin110111111100001011…
…0010010111010000111
3102111002010010102112002
41233320112102322013
53432011430224200
6131104242015515
711451644124356
oct1577026227207
9374063112462
10120130711175
1146a46722392
121b34764759b
13b4362c1767
145b5884d99d
1531d16c4bd5
hex1bf8592e87

120130711175 has 6 divisors (see below), whose sum is σ = 148962081888. Its totient is φ = 96104568920.

The previous prime is 120130711159. The next prime is 120130711237. The reversal of 120130711175 is 571117031021.

It is not a de Polignac number, because 120130711175 - 24 = 120130711159 is a prime.

It is a super-2 number, since 2×1201307111752 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2402614199 + ... + 2402614248.

It is an arithmetic number, because the mean of its divisors is an integer number (24827013648).

Almost surely, 2120130711175 is an apocalyptic number.

120130711175 is a deficient number, since it is larger than the sum of its proper divisors (28831370713).

120130711175 is an equidigital number, since it uses as much as digits as its factorization.

120130711175 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4805228457 (or 4805228452 counting only the distinct ones).

The product of its (nonzero) digits is 1470, while the sum is 29.

Adding to 120130711175 its reverse (571117031021), we get a palindrome (691247742196).

The spelling of 120130711175 in words is "one hundred twenty billion, one hundred thirty million, seven hundred eleven thousand, one hundred seventy-five".

Divisors: 1 5 25 4805228447 24026142235 120130711175