Base | Representation |
---|---|
bin | 1010111011010000010010… |
… | …0011110000011001110101 |
3 | 1120112102220121001111220211 |
4 | 2232310010203300121311 |
5 | 3033310312100242302 |
6 | 41314424132425421 |
7 | 2346626550160546 |
oct | 256640443603165 |
9 | 46472817044824 |
10 | 12013100009077 |
11 | 39117aa857592 |
12 | 1420276a78271 |
13 | 691aa470924b |
14 | 2d761973c4cd |
15 | 15c74d029ad7 |
hex | aed048f0675 |
12013100009077 has 2 divisors, whose sum is σ = 12013100009078. Its totient is φ = 12013100009076.
The previous prime is 12013100009039. The next prime is 12013100009111. The reversal of 12013100009077 is 77090000131021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12010424947236 + 2675061841 = 3465606^2 + 51721^2 .
It is a cyclic number.
It is not a de Polignac number, because 12013100009077 - 223 = 12013091620469 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12013100006077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006550004538 + 6006550004539.
It is an arithmetic number, because the mean of its divisors is an integer number (6006550004539).
Almost surely, 212013100009077 is an apocalyptic number.
It is an amenable number.
12013100009077 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013100009077 is an equidigital number, since it uses as much as digits as its factorization.
12013100009077 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2646, while the sum is 31.
The spelling of 12013100009077 in words is "twelve trillion, thirteen billion, one hundred million, nine thousand, seventy-seven".
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