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12013100303227 is a prime number
BaseRepresentation
bin1010111011010000010010…
…0100111000001101111011
31120112102220121121110102021
42232310010210320031323
53033310312134200402
641314424143015311
72346626552524252
oct256640444701573
946472817543367
1012013100303227
1139117aaa38591
121420276b9a537
13691aa47b00ba
142d76197b7799
1515c74d086d37
hexaed0493837b

12013100303227 has 2 divisors, whose sum is σ = 12013100303228. Its totient is φ = 12013100303226.

The previous prime is 12013100303219. The next prime is 12013100303327. The reversal of 12013100303227 is 72230300131021.

It is a happy number.

12013100303227 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (72230300131021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12013100303227 - 23 = 12013100303219 is a prime.

It is a super-2 number, since 2×120131003032272 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12013100303207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006550151613 + 6006550151614.

It is an arithmetic number, because the mean of its divisors is an integer number (6006550151614).

Almost surely, 212013100303227 is an apocalyptic number.

12013100303227 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013100303227 is an equidigital number, since it uses as much as digits as its factorization.

12013100303227 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 12013100303227 its reverse (72230300131021), we get a palindrome (84243400434248).

The spelling of 12013100303227 in words is "twelve trillion, thirteen billion, one hundred million, three hundred three thousand, two hundred twenty-seven".