12013101110011 has 4 divisors (see below), whose sum is σ = 12013697935800. Its totient is φ = 12012504284224.

The previous prime is 12013101110009. The next prime is 12013101110029. The reversal of 12013101110011 is 11001110131021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12013101110011 - 2¹ = 12013101110009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12013101109973 and 12013101110000.

It is not an unprimeable number, because it can be changed into a prime (12013101110411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298382701 + ... + 298422958.

It is an arithmetic number, because the mean of its divisors is an integer number (3003424483950).

Almost surely, 2^{12013101110011} is an apocalyptic number.

12013101110011 is a deficient number, since it is larger than the sum of its proper divisors (596825789).

12013101110011 is an equidigital number, since it uses as much as digits as its factorization.

12013101110011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 596825788.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 12013101110011 its reverse (11001110131021), we get a palindrome (23014211241032).

It can be divided in two parts, 120 and 13101110011, that added together give a palindrome (13101110131).

The spelling of 12013101110011 in words is "twelve trillion, thirteen billion, one hundred one million, one hundred ten thousand, eleven".