Base | Representation |
---|---|
bin | 1010111011010000010010… |
… | …1000011010100001011011 |
3 | 1120112102220200100112221112 |
4 | 2232310010220122201123 |
5 | 3033310312403331141 |
6 | 41314424214530535 |
7 | 2346626563434566 |
oct | 256640450324133 |
9 | 46472820315845 |
10 | 12013101230171 |
11 | 3911800510a58 |
12 | 1420277366a4b |
13 | 691aa4a45ca2 |
14 | 2d76199794dd |
15 | 15c74d1bb7eb |
hex | aed04a1a85b |
12013101230171 has 2 divisors, whose sum is σ = 12013101230172. Its totient is φ = 12013101230170.
The previous prime is 12013101230153. The next prime is 12013101230209. The reversal of 12013101230171 is 17103210131021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12013101230171 is a prime.
It is not a weakly prime, because it can be changed into another prime (12013101230131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006550615085 + 6006550615086.
It is an arithmetic number, because the mean of its divisors is an integer number (6006550615086).
Almost surely, 212013101230171 is an apocalyptic number.
12013101230171 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013101230171 is an equidigital number, since it uses as much as digits as its factorization.
12013101230171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 23.
Adding to 12013101230171 its reverse (17103210131021), we get a palindrome (29116311361192).
The spelling of 12013101230171 in words is "twelve trillion, thirteen billion, one hundred one million, two hundred thirty thousand, one hundred seventy-one".
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