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12013102102003 = 29341000348471
BaseRepresentation
bin1010111011010000010010…
…1011101111010111110011
31120112102220201222211212121
42232310010223233113303
53033310313114231003
641314424245335111
72346626604025432
oct256640453572763
946472821884777
1012013102102003
113911800a56a82
121420277707497
13691aa4c8ca72
142d7619b25119
1515c74d2decbd
hexaed04aef5f3

12013102102003 has 4 divisors (see below), whose sum is σ = 12054102450768. Its totient is φ = 11972101753240.

The previous prime is 12013102101887. The next prime is 12013102102007. The reversal of 12013102102003 is 30020120131021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12013102102003 - 217 = 12013101970931 is a prime.

It is a super-2 number, since 2×120131021020032 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12013102102007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20500173943 + ... + 20500174528.

It is an arithmetic number, because the mean of its divisors is an integer number (3013525612692).

Almost surely, 212013102102003 is an apocalyptic number.

12013102102003 is a deficient number, since it is larger than the sum of its proper divisors (41000348765).

12013102102003 is an equidigital number, since it uses as much as digits as its factorization.

12013102102003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41000348764.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12013102102003 its reverse (30020120131021), we get a palindrome (42033222233024).

The spelling of 12013102102003 in words is "twelve trillion, thirteen billion, one hundred two million, one hundred two thousand, three".

Divisors: 1 293 41000348471 12013102102003