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120131032169 is a prime number
BaseRepresentation
bin110111111100001011…
…1100001010001101001
3102111002010201201211202
41233320113201101221
53432012021012134
6131104252533545
711451646632251
oct1577027412151
9374063651752
10120131032169
1146a46921575
121b3477812b5
13b4363a48b5
145b588d4961
1531d1739d7e
hex1bf85e1469

120131032169 has 2 divisors, whose sum is σ = 120131032170. Its totient is φ = 120131032168.

The previous prime is 120131032067. The next prime is 120131032171. The reversal of 120131032169 is 961230131021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85474369600 + 34656662569 = 292360^2 + 186163^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120131032169 is a prime.

It is a super-2 number, since 2×1201310321692 (a number of 23 digits) contains 22 as substring.

Together with 120131032171, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (120131034169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065516084 + 60065516085.

It is an arithmetic number, because the mean of its divisors is an integer number (60065516085).

Almost surely, 2120131032169 is an apocalyptic number.

It is an amenable number.

120131032169 is a deficient number, since it is larger than the sum of its proper divisors (1).

120131032169 is an equidigital number, since it uses as much as digits as its factorization.

120131032169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 29.

The spelling of 120131032169 in words is "one hundred twenty billion, one hundred thirty-one million, thirty-two thousand, one hundred sixty-nine".