12013103301 has 4 divisors (see below), whose sum is σ = 16017471072. Its totient is φ = 8008735532.

The previous prime is 12013103299. The next prime is 12013103303. The reversal of 12013103301 is 10330131021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (12013103299) and next prime (12013103303).

It is a cyclic number.

It is not a de Polignac number, because 12013103301 - 2¹ = 12013103299 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013103303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002183881 + ... + 2002183886.

It is an arithmetic number, because the mean of its divisors is an integer number (4004367768).

Almost surely, 2^12013103301 is an apocalyptic number.

It is an amenable number.

12013103301 is a deficient number, since it is larger than the sum of its proper divisors (4004367771).

12013103301 is an equidigital number, since it uses as much as digits as its factorization.

12013103301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4004367770.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 12013103301 its reverse (10330131021), we get a palindrome (22343234322).

The spelling of 12013103301 in words is "twelve billion, thirteen million, one hundred three thousand, three hundred one".