Base | Representation |
---|---|
bin | 1010111011010000010101… |
… | …0111000000010000001110 |
3 | 1120112102221112100001021012 |
4 | 2232310011113000100032 |
5 | 3033310324020141332 |
6 | 41314425332405222 |
7 | 2346630102312524 |
oct | 256640527002016 |
9 | 46472845301235 |
10 | 12013113443342 |
11 | 39118073a2990 |
12 | 142027b476812 |
13 | 691aa743100b |
14 | 2d761b438314 |
15 | 15c74e2d03b2 |
hex | aed055c040e |
12013113443342 has 64 divisors (see below), whose sum is σ = 20082152401344. Its totient is φ = 5343947965440.
The previous prime is 12013113443329. The next prime is 12013113443389. The reversal of 12013113443342 is 24334431131021.
It is a junction number, because it is equal to n+sod(n) for n = 12013113443299 and 12013113443308.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 117959588 + ... + 118061384.
It is an arithmetic number, because the mean of its divisors is an integer number (313783631271).
Almost surely, 212013113443342 is an apocalyptic number.
12013113443342 is a deficient number, since it is larger than the sum of its proper divisors (8069038958002).
12013113443342 is a wasteful number, since it uses less digits than its factorization.
12013113443342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102453.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 12013113443342 its reverse (24334431131021), we get a palindrome (36347544574363).
The spelling of 12013113443342 in words is "twelve trillion, thirteen billion, one hundred thirteen million, four hundred forty-three thousand, three hundred forty-two".
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