1201311723511 has 4 divisors (see below), whose sum is σ = 1240063714624. Its totient is φ = 1162559732400.

The previous prime is 1201311723473. The next prime is 1201311723607. The reversal of 1201311723511 is 1153271131021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201311723511 - 2⁷ = 1201311723383 is a prime.

It is a super-5 number, since 5×1201311723511⁵ (a number of 62 digits) contains 55555 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1201311723511.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201311723811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19375995510 + ... + 19375995571.

It is an arithmetic number, because the mean of its divisors is an integer number (310015928656).

Almost surely, 2^{1201311723511} is an apocalyptic number.

1201311723511 is a deficient number, since it is larger than the sum of its proper divisors (38751991113).

1201311723511 is an equidigital number, since it uses as much as digits as its factorization.

1201311723511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38751991112.

The product of its (nonzero) digits is 1260, while the sum is 28.

Adding to 1201311723511 its reverse (1153271131021), we get a palindrome (2354582854532).

The spelling of 1201311723511 in words is "one trillion, two hundred one billion, three hundred eleven million, seven hundred twenty-three thousand, five hundred eleven".