Base | Representation |
---|---|
bin | 10110011000000100… |
… | …11010101000000011 |
3 | 1011000012210201121111 |
4 | 23030002122220003 |
5 | 144100324320003 |
6 | 5304014504151 |
7 | 603460556323 |
oct | 131402325003 |
9 | 34005721544 |
10 | 12013120003 |
11 | 5105102955 |
12 | 23b3205057 |
13 | 1195aa9541 |
14 | 81d675283 |
15 | 4a49b2e6d |
hex | 2cc09aa03 |
12013120003 has 4 divisors (see below), whose sum is σ = 12337798960. Its totient is φ = 11688441048.
The previous prime is 12013120001. The next prime is 12013120013. The reversal of 12013120003 is 30002131021.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30002131021 = 67961 ⋅441461.
It is a cyclic number.
It is not a de Polignac number, because 12013120003 - 21 = 12013120001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12013120001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162339423 + ... + 162339496.
It is an arithmetic number, because the mean of its divisors is an integer number (3084449740).
Almost surely, 212013120003 is an apocalyptic number.
12013120003 is a deficient number, since it is larger than the sum of its proper divisors (324678957).
12013120003 is an equidigital number, since it uses as much as digits as its factorization.
12013120003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 324678956.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 12013120003 its reverse (30002131021), we get a palindrome (42015251024).
The spelling of 12013120003 in words is "twelve billion, thirteen million, one hundred twenty thousand, three".
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