120131211301261 has 2 divisors, whose sum is σ = 120131211301262. Its totient is φ = 120131211301260.

The previous prime is 120131211301207. The next prime is 120131211301313. The reversal of 120131211301261 is 162103112131021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115218627192036 + 4912584109225 = 10733994^2 + 2216435^2 .

It is an emirp because it is prime and its reverse (162103112131021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120131211301261 - 2¹¹ = 120131211299213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120131211301061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065605650630 + 60065605650631.

It is an arithmetic number, because the mean of its divisors is an integer number (60065605650631).

Almost surely, 2^{120131211301261} is an apocalyptic number.

It is an amenable number.

120131211301261 is a deficient number, since it is larger than the sum of its proper divisors (1).

120131211301261 is an equidigital number, since it uses as much as digits as its factorization.

120131211301261 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 120131211301261 its reverse (162103112131021), we get a palindrome (282234323432282).

The spelling of 120131211301261 in words is "one hundred twenty trillion, one hundred thirty-one billion, two hundred eleven million, three hundred one thousand, two hundred sixty-one".