1201312131011 has 4 divisors (see below), whose sum is σ = 1201591705272. Its totient is φ = 1201032556752.

The previous prime is 1201312131001. The next prime is 1201312131013. The reversal of 1201312131011 is 1101312131021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201312131011 is a prime.

It is a super-2 number, since 2×1201312131011² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1201312131013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139780685 + ... + 139789278.

It is an arithmetic number, because the mean of its divisors is an integer number (300397926318).

Almost surely, 2^{1201312131011} is an apocalyptic number.

1201312131011 is a deficient number, since it is larger than the sum of its proper divisors (279574261).

1201312131011 is an equidigital number, since it uses as much as digits as its factorization.

1201312131011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 279574260.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1201312131011 its reverse (1101312131021), we get a palindrome (2302624262032).

The spelling of 1201312131011 in words is "one trillion, two hundred one billion, three hundred twelve million, one hundred thirty-one thousand, eleven".