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12013122014 = 2137296314797
BaseRepresentation
bin10110011000000100…
…11011000111011110
31011000012210211100222
423030002123013132
5144100324401024
65304014521342
7603460565225
oct131402330736
934005724328
1012013122014
115105104413
1223b3206252
131195aaa42a
1481d675cbc
154a49b385e
hex2cc09b1de

12013122014 has 16 divisors (see below), whose sum is σ = 18158566608. Its totient is φ = 5960302272.

The previous prime is 12013122007. The next prime is 12013122041. The reversal of 12013122014 is 41022131021.

12013122014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-4 number, since 4×120131220144 (a number of 41 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12013121983 and 12013122001.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 804464 + ... + 819260.

It is an arithmetic number, because the mean of its divisors is an integer number (1134910413).

Almost surely, 212013122014 is an apocalyptic number.

12013122014 is a deficient number, since it is larger than the sum of its proper divisors (6145444594).

12013122014 is a wasteful number, since it uses less digits than its factorization.

12013122014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17899.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 12013122014 its reverse (41022131021), we get a palindrome (53035253035).

The spelling of 12013122014 in words is "twelve billion, thirteen million, one hundred twenty-two thousand, fourteen".

Divisors: 1 2 137 274 2963 5926 14797 29594 405931 811862 2027189 4054378 43843511 87687022 6006561007 12013122014