Base | Representation |
---|---|
bin | 10110011000000100… |
… | …11011000111011110 |
3 | 1011000012210211100222 |
4 | 23030002123013132 |
5 | 144100324401024 |
6 | 5304014521342 |
7 | 603460565225 |
oct | 131402330736 |
9 | 34005724328 |
10 | 12013122014 |
11 | 5105104413 |
12 | 23b3206252 |
13 | 1195aaa42a |
14 | 81d675cbc |
15 | 4a49b385e |
hex | 2cc09b1de |
12013122014 has 16 divisors (see below), whose sum is σ = 18158566608. Its totient is φ = 5960302272.
The previous prime is 12013122007. The next prime is 12013122041. The reversal of 12013122014 is 41022131021.
12013122014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-4 number, since 4×120131220144 (a number of 41 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12013121983 and 12013122001.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 804464 + ... + 819260.
It is an arithmetic number, because the mean of its divisors is an integer number (1134910413).
Almost surely, 212013122014 is an apocalyptic number.
12013122014 is a deficient number, since it is larger than the sum of its proper divisors (6145444594).
12013122014 is a wasteful number, since it uses less digits than its factorization.
12013122014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17899.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 12013122014 its reverse (41022131021), we get a palindrome (53035253035).
The spelling of 12013122014 in words is "twelve billion, thirteen million, one hundred twenty-two thousand, fourteen".
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