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12013122543 = 34004374181
BaseRepresentation
bin10110011000000100…
…11011001111101111
31011000012210212002120
423030002123033233
5144100324410133
65304014524023
7603460566612
oct131402331757
934005725076
1012013122543
115105104854
1223b3206613
131195aaa746
1481d676179
154a49b3ab3
hex2cc09b3ef

12013122543 has 4 divisors (see below), whose sum is σ = 16017496728. Its totient is φ = 8008748360.

The previous prime is 12013122523. The next prime is 12013122551. The reversal of 12013122543 is 34522131021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12013122543 - 214 = 12013106159 is a prime.

It is a super-2 number, since 2×120131225432 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013122503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002187088 + ... + 2002187093.

It is an arithmetic number, because the mean of its divisors is an integer number (4004374182).

Almost surely, 212013122543 is an apocalyptic number.

12013122543 is a deficient number, since it is larger than the sum of its proper divisors (4004374185).

12013122543 is an equidigital number, since it uses as much as digits as its factorization.

12013122543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4004374184.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 12013122543 its reverse (34522131021), we get a palindrome (46535253564).

The spelling of 12013122543 in words is "twelve billion, thirteen million, one hundred twenty-two thousand, five hundred forty-three".

Divisors: 1 3 4004374181 12013122543