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1201313032341 = 33710822639931
BaseRepresentation
bin10001011110110011110…
…101100010100010010101
311020211210120102001201220
4101132303311202202111
5124140242114013331
62315513043240553
7152535441202452
oct21366365424225
94224716361656
101201313032341
11423523985794
121749a5379159
138938b636816
1442202a7c829
15213b0102296
hex117b3d62895

1201313032341 has 8 divisors (see below), whose sum is σ = 1645041269664. Its totient is φ = 779230074960.

The previous prime is 1201313032327. The next prime is 1201313032351. The reversal of 1201313032341 is 1432303131021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1201313032341 - 215 = 1201312999573 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201313032351) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5411319855 + ... + 5411320076.

It is an arithmetic number, because the mean of its divisors is an integer number (205630158708).

Almost surely, 21201313032341 is an apocalyptic number.

It is an amenable number.

1201313032341 is a deficient number, since it is larger than the sum of its proper divisors (443728237323).

1201313032341 is a wasteful number, since it uses less digits than its factorization.

1201313032341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10822639971.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 1201313032341 its reverse (1432303131021), we get a palindrome (2633616163362).

The spelling of 1201313032341 in words is "one trillion, two hundred one billion, three hundred thirteen million, thirty-two thousand, three hundred forty-one".

Divisors: 1 3 37 111 10822639931 32467919793 400437677447 1201313032341