1201313121301 has 4 divisors (see below), whose sum is σ = 1240065157504. Its totient is φ = 1162561085100.

The previous prime is 1201313121293. The next prime is 1201313121341. The reversal of 1201313121301 is 1031213131021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1201313121301 - 2³ = 1201313121293 is a prime.

It is a super-2 number, since 2×1201313121301² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201313121341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19376018055 + ... + 19376018116.

It is an arithmetic number, because the mean of its divisors is an integer number (310016289376).

Almost surely, 2^{1201313121301} is an apocalyptic number.

It is an amenable number.

1201313121301 is a deficient number, since it is larger than the sum of its proper divisors (38752036203).

1201313121301 is an equidigital number, since it uses as much as digits as its factorization.

1201313121301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38752036202.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1201313121301 its reverse (1031213131021), we get a palindrome (2232526252322).

The spelling of 1201313121301 in words is "one trillion, two hundred one billion, three hundred thirteen million, one hundred twenty-one thousand, three hundred one".