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1201313122 = 2600656561
BaseRepresentation
bin100011110011010…
…1001010101100010
310002201111000210121
41013212221111202
54430014004442
6315112150454
741524664422
oct10746512542
93081430717
101201313122
11567123369
1229639842a
13161b64089
14b5792482
15706e9967
hex479a9562

1201313122 has 4 divisors (see below), whose sum is σ = 1801969686. Its totient is φ = 600656560.

The previous prime is 1201313119. The next prime is 1201313129. The reversal of 1201313122 is 2213131021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 2213131021 = 11083199687.

It can be written as a sum of positive squares in only one way, i.e., 1158789681 + 42523441 = 34041^2 + 6521^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1201313096 and 1201313105.

It is not an unprimeable number, because it can be changed into a prime (1201313129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300328279 + ... + 300328282.

Almost surely, 21201313122 is an apocalyptic number.

1201313122 is a deficient number, since it is larger than the sum of its proper divisors (600656564).

1201313122 is an equidigital number, since it uses as much as digits as its factorization.

1201313122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 600656563.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1201313122 is about 34659.9642527225. The cubic root of 1201313122 is about 1063.0460390921.

Adding to 1201313122 its reverse (2213131021), we get a palindrome (3414444143).

The spelling of 1201313122 in words is "one billion, two hundred one million, three hundred thirteen thousand, one hundred twenty-two".

Divisors: 1 2 600656561 1201313122