12013131233011 has 4 divisors (see below), whose sum is σ = 12013138210024. Its totient is φ = 12013124256000.

The previous prime is 12013131232969. The next prime is 12013131233017. The reversal of 12013131233011 is 11033213131021.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12013131233011 is a prime.

It is a super-2 number, since 2×12013131233011² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12013131233017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1150771 + ... + 5034931.

It is an arithmetic number, because the mean of its divisors is an integer number (3003284552506).

Almost surely, 2^{12013131233011} is an apocalyptic number.

12013131233011 is a deficient number, since it is larger than the sum of its proper divisors (6977013).

12013131233011 is an equidigital number, since it uses as much as digits as its factorization.

12013131233011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6977012.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 12013131233011 its reverse (11033213131021), we get a palindrome (23046344364032).

The spelling of 12013131233011 in words is "twelve trillion, thirteen billion, one hundred thirty-one million, two hundred thirty-three thousand, eleven".