1201313202231 has 8 divisors (see below), whose sum is σ = 1607451118704. Its totient is φ = 798025376960.

The previous prime is 1201313202169. The next prime is 1201313202263. The reversal of 1201313202231 is 1322023131021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1201313202231 - 2⁹ = 1201313201719 is a prime.

It is a super-2 number, since 2×1201313202231² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1201313202198 and 1201313202207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201313202031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 712521816 + ... + 712523501.

It is an arithmetic number, because the mean of its divisors is an integer number (200931389838).

Almost surely, 2^{1201313202231} is an apocalyptic number.

1201313202231 is a deficient number, since it is larger than the sum of its proper divisors (406137916473).

1201313202231 is a wasteful number, since it uses less digits than its factorization.

1201313202231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1425045601.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1201313202231 its reverse (1322023131021), we get a palindrome (2523336333252).

The spelling of 1201313202231 in words is "one trillion, two hundred one billion, three hundred thirteen million, two hundred two thousand, two hundred thirty-one".