Base | Representation |
---|---|
bin | 10001011110110011110… |
… | …110100110010110110010 |
3 | 11020211210120221011210101 |
4 | 101132303312212112302 |
5 | 124140242201411010 |
6 | 2315513053223014 |
7 | 152535443440363 |
oct | 21366366462662 |
9 | 4224716834711 |
10 | 1201313310130 |
11 | 42352405546a |
12 | 1749a5491a6a |
13 | 8938b7030ab |
14 | 42202b11b6a |
15 | 213b015973a |
hex | 117b3da65b2 |
1201313310130 has 16 divisors (see below), whose sum is σ = 2162405029824. Its totient is φ = 480516197040.
The previous prime is 1201313310121. The next prime is 1201313310133. The reversal of 1201313310130 is 310133131021.
It is a junction number, because it is equal to n+sod(n) for n = 1201313310098 and 1201313310107.
It is not an unprimeable number, because it can be changed into a prime (1201313310133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 574686 + ... + 1653145.
It is an arithmetic number, because the mean of its divisors is an integer number (135150314364).
Almost surely, 21201313310130 is an apocalyptic number.
1201313310130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1201313310130 is a deficient number, since it is larger than the sum of its proper divisors (961091719694).
1201313310130 is a wasteful number, since it uses less digits than its factorization.
1201313310130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2281761.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1201313310130 its reverse (310133131021), we get a palindrome (1511446441151).
The spelling of 1201313310130 in words is "one trillion, two hundred one billion, three hundred thirteen million, three hundred ten thousand, one hundred thirty".
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