12013140121 has 2 divisors, whose sum is σ = 12013140122. Its totient is φ = 12013140120.

The previous prime is 12013140107. The next prime is 12013140137. The reversal of 12013140121 is 12104131021.

It is an a-pointer prime, because the next prime (12013140137) can be obtained adding 12013140121 to its sum of digits (16).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9616548096 + 2396592025 = 98064^2 + 48955^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013140121 - 2⁷ = 12013139993 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12013140095 and 12013140104.

It is not a weakly prime, because it can be changed into another prime (12013140101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006570060 + 6006570061.

It is an arithmetic number, because the mean of its divisors is an integer number (6006570061).

Almost surely, 2^12013140121 is an apocalyptic number.

It is an amenable number.

12013140121 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013140121 is an equidigital number, since it uses as much as digits as its factorization.

12013140121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12013140121 its reverse (12104131021), we get a palindrome (24117271142).

The spelling of 12013140121 in words is "twelve billion, thirteen million, one hundred forty thousand, one hundred twenty-one".