1201314132101 has 2 divisors, whose sum is σ = 1201314132102. Its totient is φ = 1201314132100.

The previous prime is 1201314132089. The next prime is 1201314132127. The reversal of 1201314132101 is 1012314131021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1194487241476 + 6826890625 = 1092926^2 + 82625^2 .

It is an emirp because it is prime and its reverse (1012314131021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1201314132101 - 2¹⁴ = 1201314115717 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201314132131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600657066050 + 600657066051.

It is an arithmetic number, because the mean of its divisors is an integer number (600657066051).

Almost surely, 2^{1201314132101} is an apocalyptic number.

It is an amenable number.

1201314132101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201314132101 is an equidigital number, since it uses as much as digits as its factorization.

1201314132101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1201314132101 its reverse (1012314131021), we get a palindrome (2213628263122).

The spelling of 1201314132101 in words is "one trillion, two hundred one billion, three hundred fourteen million, one hundred thirty-two thousand, one hundred one".