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120131424041 is a prime number
BaseRepresentation
bin110111111100001100…
…1000000111100101001
3102111002011110122101112
41233320121000330221
53432012121032131
6131104305200105
711451653153606
oct1577031007451
9374064418345
10120131424041
1146a47069a32
121b347930035
13b4364b1085
145b589976ad
1531d17b602b
hex1bf8640f29

120131424041 has 2 divisors, whose sum is σ = 120131424042. Its totient is φ = 120131424040.

The previous prime is 120131424031. The next prime is 120131424059. The reversal of 120131424041 is 140424131021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83003914816 + 37127509225 = 288104^2 + 192685^2 .

It is a cyclic number.

It is not a de Polignac number, because 120131424041 - 210 = 120131423017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120131423998 and 120131424016.

It is not a weakly prime, because it can be changed into another prime (120131424031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065712020 + 60065712021.

It is an arithmetic number, because the mean of its divisors is an integer number (60065712021).

Almost surely, 2120131424041 is an apocalyptic number.

It is an amenable number.

120131424041 is a deficient number, since it is larger than the sum of its proper divisors (1).

120131424041 is an equidigital number, since it uses as much as digits as its factorization.

120131424041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 120131424041 its reverse (140424131021), we get a palindrome (260555555062).

The spelling of 120131424041 in words is "one hundred twenty billion, one hundred thirty-one million, four hundred twenty-four thousand, forty-one".