120132000040001 has 2 divisors, whose sum is σ = 120132000040002. Its totient is φ = 120132000040000.

The previous prime is 120132000039977. The next prime is 120132000040081. The reversal of 120132000040001 is 100040000231021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109646553000625 + 10485447039376 = 10471225^2 + 3238124^2 .

It is a cyclic number.

It is not a de Polignac number, because 120132000040001 - 2²⁶ = 120131932931137 is a prime.

It is a super-2 number, since 2×120132000040001² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120132000040081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066000020000 + 60066000020001.

It is an arithmetic number, because the mean of its divisors is an integer number (60066000020001).

Almost surely, 2^{120132000040001} is an apocalyptic number.

It is an amenable number.

120132000040001 is a deficient number, since it is larger than the sum of its proper divisors (1).

120132000040001 is an equidigital number, since it uses as much as digits as its factorization.

120132000040001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 120132000040001 its reverse (100040000231021), we get a palindrome (220172000271022).

The spelling of 120132000040001 in words is "one hundred twenty trillion, one hundred thirty-two billion, forty thousand, one".