Base | Representation |
---|---|
bin | 10110011000000101… |
… | …01110011110110011 |
3 | 1011000012221212011122 |
4 | 23030002232132303 |
5 | 144100334420311 |
6 | 5304020332455 |
7 | 603461345405 |
oct | 131402563663 |
9 | 34005855148 |
10 | 12013201331 |
11 | 5105158a6a |
12 | 23b324412b |
13 | 1195b07571 |
14 | 81d696b75 |
15 | 4a49cc0db |
hex | 2cc0ae7b3 |
12013201331 has 2 divisors, whose sum is σ = 12013201332. Its totient is φ = 12013201330.
The previous prime is 12013201297. The next prime is 12013201379. The reversal of 12013201331 is 13310231021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12013201331 is a prime.
It is a super-2 number, since 2×120132013312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12013201391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006600665 + 6006600666.
It is an arithmetic number, because the mean of its divisors is an integer number (6006600666).
Almost surely, 212013201331 is an apocalyptic number.
12013201331 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013201331 is an equidigital number, since it uses as much as digits as its factorization.
12013201331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 12013201331 its reverse (13310231021), we get a palindrome (25323432352).
The spelling of 12013201331 in words is "twelve billion, thirteen million, two hundred one thousand, three hundred thirty-one".
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