Base | Representation |
---|---|
bin | 10001011110110100011… |
… | …011100101000011100001 |
3 | 11020211211021011200110101 |
4 | 101132310123211003201 |
5 | 124140302142113004 |
6 | 2315514041102401 |
7 | 152535622023643 |
oct | 21366433450341 |
9 | 4224737150411 |
10 | 1201323004129 |
11 | 423529576736 |
12 | 1749a8787a01 |
13 | 893907185a1 |
14 | 42204116893 |
15 | 213b0e21ba4 |
hex | 117b46e50e1 |
1201323004129 has 2 divisors, whose sum is σ = 1201323004130. Its totient is φ = 1201323004128.
The previous prime is 1201323004117. The next prime is 1201323004153. The reversal of 1201323004129 is 9214003231021.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1153158117904 + 48164886225 = 1073852^2 + 219465^2 .
It is a cyclic number.
It is not a de Polignac number, because 1201323004129 - 213 = 1201322995937 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201323004097 and 1201323004106.
It is not a weakly prime, because it can be changed into another prime (1201323004109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600661502064 + 600661502065.
It is an arithmetic number, because the mean of its divisors is an integer number (600661502065).
Almost surely, 21201323004129 is an apocalyptic number.
It is an amenable number.
1201323004129 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201323004129 is an equidigital number, since it uses as much as digits as its factorization.
1201323004129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
The spelling of 1201323004129 in words is "one trillion, two hundred one billion, three hundred twenty-three million, four thousand, one hundred twenty-nine".
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