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1201323004129 is a prime number
BaseRepresentation
bin10001011110110100011…
…011100101000011100001
311020211211021011200110101
4101132310123211003201
5124140302142113004
62315514041102401
7152535622023643
oct21366433450341
94224737150411
101201323004129
11423529576736
121749a8787a01
13893907185a1
1442204116893
15213b0e21ba4
hex117b46e50e1

1201323004129 has 2 divisors, whose sum is σ = 1201323004130. Its totient is φ = 1201323004128.

The previous prime is 1201323004117. The next prime is 1201323004153. The reversal of 1201323004129 is 9214003231021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1153158117904 + 48164886225 = 1073852^2 + 219465^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201323004129 - 213 = 1201322995937 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201323004097 and 1201323004106.

It is not a weakly prime, because it can be changed into another prime (1201323004109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600661502064 + 600661502065.

It is an arithmetic number, because the mean of its divisors is an integer number (600661502065).

Almost surely, 21201323004129 is an apocalyptic number.

It is an amenable number.

1201323004129 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201323004129 is an equidigital number, since it uses as much as digits as its factorization.

1201323004129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 28.

The spelling of 1201323004129 in words is "one trillion, two hundred one billion, three hundred twenty-three million, four thousand, one hundred twenty-nine".