1201323113 has 8 divisors (see below), whose sum is σ = 1222537128. Its totient is φ = 1180237824.

The previous prime is 1201323107. The next prime is 1201323119. The reversal of 1201323113 is 3113231021.

It is an interprime number because it is at equal distance from previous prime (1201323107) and next prime (1201323119).

It can be written as a sum of positive squares in 4 ways, for example, as 912764944 + 288558169 = 30212^2 + 16987^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1201323113 - 2¹² = 1201319017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1201323091 and 1201323100.

It is not an unprimeable number, because it can be changed into a prime (1201323119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13256 + ... + 50777.

It is an arithmetic number, because the mean of its divisors is an integer number (152817141).

Almost surely, 2^1201323113 is an apocalyptic number.

It is an amenable number.

1201323113 is a deficient number, since it is larger than the sum of its proper divisors (21214015).

1201323113 is an equidigital number, since it uses as much as digits as its factorization.

1201323113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64363.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 1201323113 is about 34660.1083812501. The cubic root of 1201323113 is about 1063.0489861071.

Adding to 1201323113 its reverse (3113231021), we get a palindrome (4314554134).

The spelling of 1201323113 in words is "one billion, two hundred one million, three hundred twenty-three thousand, one hundred thirteen".