Base | Representation |
---|---|
bin | 1010111011010000110001… |
… | …1100011010110011001111 |
3 | 1120112110020210222202111021 |
4 | 2232310030130122303033 |
5 | 3033311044432201221 |
6 | 41314445220135011 |
7 | 2346633044515201 |
oct | 256641434326317 |
9 | 46473223882437 |
10 | 12013232303311 |
11 | 39118684a6168 |
12 | 14202b3237467 |
13 | 691ac5c49065 |
14 | 2d762d138771 |
15 | 15c75995d041 |
hex | aed0c71accf |
12013232303311 has 4 divisors (see below), whose sum is σ = 12030821223912. Its totient is φ = 11995643382712.
The previous prime is 12013232303309. The next prime is 12013232303323. The reversal of 12013232303311 is 11330323231021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12013232303311 - 21 = 12013232303309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12013232303411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8794459276 + ... + 8794460641.
It is an arithmetic number, because the mean of its divisors is an integer number (3007705305978).
Almost surely, 212013232303311 is an apocalyptic number.
12013232303311 is a deficient number, since it is larger than the sum of its proper divisors (17588920601).
12013232303311 is an equidigital number, since it uses as much as digits as its factorization.
12013232303311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17588920600.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 12013232303311 its reverse (11330323231021), we get a palindrome (23343555534332).
The spelling of 12013232303311 in words is "twelve trillion, thirteen billion, two hundred thirty-two million, three hundred three thousand, three hundred eleven".
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