Base | Representation |
---|---|
bin | 10110011000000101… |
… | …10110010000010101 |
3 | 1011000020000110211222 |
4 | 23030002312100111 |
5 | 144100341430143 |
6 | 5304021140125 |
7 | 603461540264 |
oct | 131402662025 |
9 | 34006013758 |
10 | 12013233173 |
11 | 510517a987 |
12 | 23b325a645 |
13 | 1195b18bc6 |
14 | 81d6a45db |
15 | 4a49d6768 |
hex | 2cc0b6415 |
12013233173 has 2 divisors, whose sum is σ = 12013233174. Its totient is φ = 12013233172.
The previous prime is 12013233137. The next prime is 12013233191. The reversal of 12013233173 is 37133231021.
Together with previous prime (12013233137) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11942555524 + 70677649 = 109282^2 + 8407^2 .
It is a cyclic number.
It is not a de Polignac number, because 12013233173 - 224 = 11996455957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12013233373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006616586 + 6006616587.
It is an arithmetic number, because the mean of its divisors is an integer number (6006616587).
Almost surely, 212013233173 is an apocalyptic number.
It is an amenable number.
12013233173 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013233173 is an equidigital number, since it uses as much as digits as its factorization.
12013233173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 26.
Adding to 12013233173 its reverse (37133231021), we get a palindrome (49146464194).
The spelling of 12013233173 in words is "twelve billion, thirteen million, two hundred thirty-three thousand, one hundred seventy-three".
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