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120132612263047 is a prime number
BaseRepresentation
bin11011010100001010001101…
…101011100000110010000111
3120202100120021022010222210111
4123110022031223200302013
5111221223042214404142
61103300054333533451
734206203056625566
oct3324121553406207
9522316238128714
10120132612263047
1135306a5585421a
1211582608944287
1352055c2579087
14219464144dbdd
15dd4dd19bce17
hex6d428dae0c87

120132612263047 has 2 divisors, whose sum is σ = 120132612263048. Its totient is φ = 120132612263046.

The previous prime is 120132612263021. The next prime is 120132612263123. The reversal of 120132612263047 is 740362216231021.

It is a weak prime.

It is an emirp because it is prime and its reverse (740362216231021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120132612263047 - 239 = 119582856449159 is a prime.

It is a congruent number.

It is a weakly prime.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066306131523 + 60066306131524.

It is an arithmetic number, because the mean of its divisors is an integer number (60066306131524).

Almost surely, 2120132612263047 is an apocalyptic number.

120132612263047 is a deficient number, since it is larger than the sum of its proper divisors (1).

120132612263047 is an equidigital number, since it uses as much as digits as its factorization.

120132612263047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 40.

Adding to 120132612263047 its reverse (740362216231021), we get a palindrome (860494828494068).

The spelling of 120132612263047 in words is "one hundred twenty trillion, one hundred thirty-two billion, six hundred twelve million, two hundred sixty-three thousand, forty-seven".