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120132631 is a prime number
BaseRepresentation
bin1110010100100…
…01010000010111
322101001100222201
413022101100113
5221223221011
615530505331
72656052623
oct712212027
9271040881
10120132631
11618a2473
1234295247
131bb723c8
1411d52183
15a82ecc1
hex7291417

120132631 has 2 divisors, whose sum is σ = 120132632. Its totient is φ = 120132630.

The previous prime is 120132589. The next prime is 120132641. The reversal of 120132631 is 136231021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120132631 - 213 = 120124439 is a prime.

It is a super-2 number, since 2×1201326312 = 28863698061964322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120132599 and 120132608.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120132641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066315 + 60066316.

It is an arithmetic number, because the mean of its divisors is an integer number (60066316).

Almost surely, 2120132631 is an apocalyptic number.

120132631 is a deficient number, since it is larger than the sum of its proper divisors (1).

120132631 is an equidigital number, since it uses as much as digits as its factorization.

120132631 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 120132631 is about 10960.5032274983. The cubic root of 120132631 is about 493.4240680544.

Adding to 120132631 its reverse (136231021), we get a palindrome (256363652).

The spelling of 120132631 in words is "one hundred twenty million, one hundred thirty-two thousand, six hundred thirty-one".