1201330123333 has 4 divisors (see below), whose sum is σ = 1204959519808. Its totient is φ = 1197700726860.

The previous prime is 1201330123289. The next prime is 1201330123361. The reversal of 1201330123333 is 3333210331021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201330123333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1201330123298 and 1201330123307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201330123363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1814697741 + ... + 1814698402.

It is an arithmetic number, because the mean of its divisors is an integer number (301239879952).

Almost surely, 2^{1201330123333} is an apocalyptic number.

It is an amenable number.

1201330123333 is a deficient number, since it is larger than the sum of its proper divisors (3629396475).

1201330123333 is an equidigital number, since it uses as much as digits as its factorization.

1201330123333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3629396474.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 1201330123333 its reverse (3333210331021), we get a palindrome (4534540454354).

The spelling of 1201330123333 in words is "one trillion, two hundred one billion, three hundred thirty million, one hundred twenty-three thousand, three hundred thirty-three".